Homework 7

Directions:

  1. Show each step of your work and fully simplify each expression.
  2. Turn in your answers in class on a physical piece of paper.
  3. Staple multiple sheets together.
  4. Feel free to use Desmos for graphing.

Answer the following:

  1. Solve for all possible triangles using the Law of Sines. Remember, you may use Desmos (in degree mode) to evaluate $\sin$ of an angle!
    1. $\angle A = 50^\circ, \qquad \angle B = 68^\circ, \qquad c = 230$
    2. $\angle A = 30^\circ, \qquad \angle C = 65^\circ, \qquad b = 10$
    3. $a = 28, \qquad b = 15, \qquad \angle A = 110^\circ$
    4. $a = 20, \qquad c = 45, \qquad \angle A = 125^\circ$
    5. $\angle A = 43.1^\circ, \qquad a = 186.2, \qquad b = 248.6$
  2. Which of the following are identities? If they are not, show with specific variable values. If you think they are, justify using reasoning based off of previous sections or prove it.
    1. $x^2 + y^2 = 1$
    2. $x(y + z) = xy + xz$
    3. $x^2 - \cos^2 x = (x - \cos x)(x + \cos x)$
    4. $\sin(x + y) = \sin(x) + \sin(y)$
  3. Simplify these expressions:
    1. $\cos t \tan t$
    2. $\dfrac{\sec x}{\csc x}$
    3. $\dfrac{\sec \theta - \cos \theta}{\sin \theta}$
    4. $\dfrac{1}{1 + \sin \theta} + \dfrac{1}{1 - \sin \theta}$
  4. Prove these identities algebraically:
    1. $\dfrac{\sin \theta}{\tan \theta} = \cos \theta$
    2. $\dfrac{\cos x}{\sec x\sin x} = \csc x - \sin x$
    3. $\dfrac{\sin \alpha \sec \alpha}{\tan \alpha} = 1$
    4. $\dfrac{(\sin x + \cos x)^2}{\sin x \cos x} = 2 + \sec x \csc x$
    5. $\sin^4 \alpha - \cos^4 \alpha = \sin^2 \alpha - \cos^2 \alpha$.
      Hint: Let $x = \sin^2 \alpha, y = \cos^2 \alpha$ and factor.
    6. $\dfrac{\cos x}{\sec x} + \dfrac{\sin x}{\csc x} = 1$
    7. $\tan \theta + \cot \theta = \sec \theta \csc \theta$
    8. $(\cot \theta - \csc \theta)(\cos \theta + 1) = -\sin\theta$
    9. $\dfrac{\sin \theta}{\tan \theta} = \cos \theta$
  5. Assume $0 < \theta < \pi/2$. Make the indicated trigonometric substitution and simplify.
    1. $\dfrac{x}{\sqrt{1 - x^2}}, \ x = \sin \theta$.
    2. $\sqrt{9 - x^2}, \ x = 3\sin \theta$