7.1: Trigonometric Identities


We have now seen what the trigonometric functions are and where they appear in real life. Let's now dive more into more algebraic-type problems of trigonometric functions.

An equation is a statement that two mathematical expressions are equal. For example, the following are equations \begin{align} x + 2 &= 5\\ (x + 1)^2 &= x^2 + 2x + 1\\ \sin^2 x + \cos^2 x &= 1 \end{align} An identity is an equation that is true for all the values of the variables in the equation. For example, in the above equation $\sin^2 x + \cos^2 x = 1$ is true for any values of $x$; we saw this was true in Section 5.2.

This section will heavily depend on identities that were introduced in Section 5.2. Make sure to keep these in your back pocket and use these often!

Simplifying Trigonometric Expressions

The first type of problem we will encounter is to simplify a complicated looking expression.

Simplfy the expression $\cos t + \tan t \sin t$.
Simplify the expression $\dfrac{\sin\theta}{\cos \theta} + \dfrac{\cos \theta}{1 + \sin \theta}$.

Strategies:

Proving Trigonometric Identities

We have two subproblems.

Show Equation is not Identity

If someone walks up to you and says "All horses are brown", to disprove this statement, you only need to find one example of a horse which is not brown, such as a zebra.

To disprove an identity, we use the same idea. For example, given $\sin x + \cos x = 1$, to disprove this statement, we only need to find one $x$ which makes this equation false (recall identity means true for all variable values).

Show the equation $\sin x + \cos x = 1$ is not an identity.

Prove Equation is Identity

Here are a few guidelines to prove an equation is actually an identity. They are not necessarily taken in order.

To prove an identity, only perform reversible operations. Non-reversible operations include
  1. Squaring both sides.
  2. Taking square roots of both sides.
Given \[\sin x = - \sin x\] try squaring both sides. What happens?

In general, you cannot start with a false initial statement, get to a true conclusion, then conclude that initial statement is true. A similar concept also appears in daily conversations and is called Argument from False Premises.

Verify algebraically that \[\cos\theta (\sec \theta - \cos \theta) = \sin^2 \theta\] Also verify graphically.
Verify this identity algebraically \[2\tan x \sec x = \frac{1}{1 - \sin x} - \frac{1}{1 + \sin x}\]
Verify this identity algebraically \[\frac{\cos \theta}{1 - \sin \theta} = \sec \theta + \tan \theta\]
Verify \[\frac{1 + \cos \theta}{\cos \theta} = \frac{\tan^2 \theta}{\sec \theta - 1}\]
Assume $0 \leq \theta \leq \pi/2$. Substitute $\sin \theta$ for $x$ in the expression $\sqrt{1 - x^2}$ and simplify.