Homework 4
Directions:
- Show each step of your work and fully simplify each expression.
- Turn in your answers in class on a physical piece of paper.
- Staple multiple sheets together.
- Feel free to use Desmos for graphing.
Answer the following:
- Suppose a student sees a function \[f(x) = \dfrac{\sqrt{x}}{x^2 + x}\] and is asked to find $\dfrac{d}{dx} f(x)$. The student tries this: \[\dfrac{d}{dx} f(x) = \dfrac{d}{dx} \dfrac{\sqrt{x}}{x + 1} = \dfrac{\dfrac{d}{dx} \sqrt{x}}{\dfrac{d}{dx} (x^2 + x)}\] Why is this incorrect?
- Suppose a student tries again. They try \[\dfrac{d}{dx} f(x) = \dfrac{x^2 + x \cdot \frac{1}{2}x^{-1/2} - x^{1/2} \cdot 2x + 1}{(x^2 + x)^2}\] Why is this still incorrect?
- Given $g(r) = \sqrt{r} + \sqrt[3]{r}$, find the first and second derivatives.
- Suppose \[f(x) = 3\cdot(x^2 - 1)\] Do you need to use the product rule to find $f'(x)$? Why or why not?
- Find the derivative using the Differentiation Rules. Remember to observe your input variable and to fully simplify each expression.
- $y = \dfrac{x^2 + 1}{x^2 - 1}$
- $y = x + \dfrac{1}{x}$
- $y = \dfrac{1 + 2x}{3 - 4x}$
- $f(x) = \dfrac{x}{x + \frac{1}{x}}$
- $f(x) = (x^2 + x + 1)(x^{-2} + x^{-3})$
- The equation of motion of a particle is $s(t) = t^4 - 2t^3 + t^2 - t$ where $s$ is in meters and $t$ is in seconds.
- Find the velocity and acceleration as functions of $t$.
- Find the acceleration when the velocity is 0. (hint: set $v(t) = 0$ to find the time when the velocity is 0).
- Find an equation of the normal line to the curve $y = \sqrt{x}$ that is parallel to the line $2x + y = 1$.
Hint:
- Find the derivative and set it equal to slope of the above line.
- Solve for $x$, this value of $x$ gives you the $x$-value of the point of tangency.
- Differentiate the following:
- $f(x) = \sec x$
- $f(x) = \cot x$
- $f(x) = x\cos x + 2\tan x$
- $f(x) = \dfrac{\sec x}{1 + \tan x}$
- $w(t) = \dfrac{\sin t}{1 - \sin t}$
- Find the 51st derivative of $f(x) = \sin x$.
- Suppose $F(x) = \sin(\cos (x))$. Finding a decomposition $f\circ g = F$, you determine that \[f(x) = x \qquad \qquad g(x) = \sin (\cos (x))\] Why is this decomposition useless when finding $F'(x)$?
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Differentiate the following. Be sure to recognize the form of the expression you are taking the derivative of in order to use the correct rule.
- $f(x) = (3x - x^3)^{23}$
- $f(x) = \sqrt[3]{1 + \tan x}$
- $f(x) = (3x + 2)^3(4x^2 + 3)^4$
- $f(x) = \dfrac{\sin^2(x)\cdot(4x^2-1)^3}{(3x^3 - 2x)^4}$
- $g(x) = \cos^3 x$
- $g(\theta) = \cos \theta^3$
- $y = \sqrt{x + \sqrt{ x + \sqrt{x}}}$
- $f(x) = \sqrt{\dfrac{x}{x^2 + 4}}$
- $f(x) = \sin x + \sin^2 x$
- $g(a) = \sin(a \sin a)$
- $f(x) = \sqrt{\sec x}$
- $f(x) = \left(\dfrac{\sin^2(x)}{(x^2 + 1)^3}\right)^4$
- Find the equation of the tangent line to the curve at the given point.
- $y = (1 + 2x)^{10}, \qquad (0, 1)$
- $y = \sin(\sin(x)), \qquad (\pi, 0)$
The rest of these problems will appear on next week's homework. Skip the rest of these for this homework.
- What is the main idea behind implicit differentiation?
- What are the four steps to isolate an entity in an equation, let's say $\dfrac{dy}{dx}$?
- Isolate $z$ in the equation \[-\sin(xy)(x + xz) = 1 + \cos(y)z\]
- Find $dy/dx$ with implicit differentiation for the equation \[x^3 + y^3 + x^2 + y = 1\]
- Consider the equation $x^{2/3} + y^{2/3} = 4$. Find the equation of the tangent line at the point $(-3\sqrt{3}, 1)$.